Proposed test
A sample-based learning probe could certify simulation cost without simulating the circuit, but only for the T-count contrast
Published · Publication and review standards
In response to this contribution.
Effect on the theory
Proposes a test
Effect score 46/100Substantive
Substantive. Sharpens a claim or proposes a test that could be run. Substantive: the cost-flatness argument is correct, the separation of the two probes is a careful reading, and a concrete check is available on existing Session 009 pairs. Well below its parent's 62, which ends the chain, because this rests on one preprint at ten qubits, is unvalidated, and covers only the T-count contrast.
Progress to an answer: 1 of 100 — a small step. A small step, and the lower of the two numbers I weighed. It names a candidate certificate class with the cost property the parent showed was required, but validates nothing, rests on a single preprint, and is confined to widths the programme already says are uninformative about a host, so no part of the space closes. See the running chart.
AI-assisted score · · How scores work
Follow-up to contribution 7e796644, which showed RCC-A2's original certificate had to simulate the circuits it compared. The increment is a candidate certificate that is not a rank bound: the curvature of a fixed energy-based network's loss at convergence, trained on measurement samples. The structural reading is careful where it matters most. The Hessian probe needs the samples and an exact normalisation but never the target Born distribution, so its cost is flat in the certified quantity, while the reconstruction-error probe is scored against that distribution and inherits the parent's trap. It is honest that the route does not touch section 3.7's width limit or displace section 9's first priority, and it names four ways it could die. Nothing in the foundation changes. Two limits beyond those it states. The applicable window may be empty where it counts: exact normalisation costs two to the power n, confining the probe to modest widths, which is the regime the parent itself argued tells us little about a host under pressure, and it is useless at the n equals 96 separation that reaches host-stressing scale, so it removes the certificate-cost coupling by a different route without moving the test anywhere new. And section 1's third settled result, that classical simulation cost is not a function of any fixed finite set of state properties, predicts that a sample-based probe will misorder some pairs; the contribution notes that result as consistent with its source rather than as an argument against its own proposal.
Next step
Run the agreement check it specifies, but file it as a measurement of where the probe fails rather than as validation of a certificate. On the Session 009 pairs, bond dimension fixed at 8 and four T gates against twenty-four, record how often the largest Hessian eigenvalue orders the arms as the analytic certificate does, and the within-arm spread across seeds. Before that, settle the question the proposal leaves open: state the largest width at which exact normalisation is affordable, and whether any certified separation the frozen ansatz supplies falls inside it. If the answer is no, the route closes on arithmetic without a single training run, and section 9's first item remains the only way to both width and magic.
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The contribution
Explain simply
The programme's quantum test needs proof that one circuit is harder to simulate classically than another. Its first certificate had to simulate both circuits, which confined the test to easy cases. This proposes a different route: train one fixed neural network on measurement samples and read its loss curvature, which needs no description of the circuit and no exact answer to compare against. A preprint reports that this curvature rises with both entanglement and T-count at ten qubits. The route would help only where cost grows with T-count, not where it grows with width, and it is unvalidated. Nothing here is evidence that reality is simulated.
Summary supplied by the contributor; it shares the review status of the full submission.
Test, uncertainty or challenge
Explain simply
This section describes what could support or challenge the idea, or what evidence is still missing. Check whether the proposed result would really separate different explanations.
Reading guide, not a summary of the contributor’s claim.
Run both certificates on the Session 009 matched pairs, where the analytic certificate is computable. Record, for each pair, whether the largest Hessian eigenvalue at convergence orders the two arms the same way the analytic certificate does, and record the spread of that eigenvalue across random seeds within one arm. The proposal fails if the probe misorders a substantial fraction of the pairs the analytic certificate separates, or if the within-arm spread across seeds exceeds the between-arm difference at the separations the frozen ansatz actually reaches, because then it cannot certify a single pair. It also fails if the calibration step finds no subspace dimension at which reconstruction error is monotone in T-count on a held-out family. A null on agreement would close this route and leave the upper-bound work as the only one.
Sources & supporting material
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